Question :
I have a carts table with items hstore column. An example entry in this column is:
carts.items row#1 = {
"1614" => {:quantity=>"100", :price_cents=>1655},
"1938" => {:quantity=>"50", :price_cents=>1955},
"1983" => {:quantity=>"100", :price_cents=>2255},
"1322" => {:quantity=>"10", :price_cents=>4455},
"1691" => {:quantity=>"25", :price_cents=>1055},
"1734" => {:quantity=>"20", :price_cents=>1255}
}
carts.items row#2 = {"1614"=>{:quantity=>"50", :price_cents=>1655}}
So my carts table would look like this:
id | items
---------+-------
1 | {"1614"=>{:quantity=>"100", :price_cents=>1655}, "1938" => {:quantity=>"50", :price_cents=>1955},"1983"=>{:quantity=>"100", :price_cents=>2255},"1322"=>{:quantity=>"10", :price_cents=>4455},"1691"=>{:quantity=>"25", :price_cents=>1055},"1734"=>{:quantity=>"20", :price_cents=>1255}}
2 | {"1614"=>{:quantity=>"50", :price_cents=>1655}}
You will notice that there is one duplicate id (1614) in the hash, but its quantity is different.
I want to write a query that will return a table with the item id counts and the total quantity. It should look like this:
item_id | count | total
---------+-------+------
1614 | 2 | 150
1938 | 1 | 50
1983 | 1 | 50
1322 | 1 | 100
Here is the query that I am working with:
SELECT
skeys(carts.items) as item_ids,
COUNT(*) AS count,
svals(carts.items) as items
FROM carts
GROUP BY
skeys(carts.items),
svals(carts.items)
It returns:
item_id | count | total
---------+-------+------
1614 | 1 | {:quantity=>100}
1614 | 1 | {:quantity=>50}
1938 | 1 | {:quantity=>50}
1983 | 1 | {:quantity=>50}
1322 | 1 | {:quantity=>100}
I aslo have tried:
SELECT key, count(*) FROM
(SELECT (each(items)).key FROM carts) AS stat
GROUP BY key
ORDER BY count DESC, key;
Which gives me this:
item_id | count
---------+-------
1614 | 2
1938 | 1
1983 | 1
1322 | 1
Answer :
Original question (dupes within hstore
value)
I think the root cause of your problems is explained in this quote from the manual:
Each key in an hstore is unique. If you declare an
hstore
with
duplicate keys, only one will be stored in thehstore
and there is no
guarantee as to which will be kept.
Bold emphasis mine.
You are mistaken in assuming that you could have the same key twice in a single hstore
value.
I can also not reproduce your count
of 2
. I get a count
of 1
for the key 1614
. Start by not using count
as column name. It is a reserved word (but allowed in Postgres).
I get (tested with Postgres 9.1.9):
WITH carts AS (
SELECT '"1614"=>{:quantity=>"100"}, "1938"=>{:quantity=>"50"}, "1614"=>{:quantity=>"50"}, "1983"=>{:quantity=>"100"}, "1322"=>{:quantity=>"10"}, "1691"=>{:quantity=>"25"}, "1614"=>{:quantity=>"77"}, "1734"=>{:quantity=>"20"}'::hstore items
)
SELECT key, count(*) AS ct FROM
(SELECT (each(items)).key FROM carts) AS stat
GROUP BY key
ORDER BY ct DESC, key;
Result:
key | ct
------+----
1322 | 1
1614 | 1
1691 | 1
1734 | 1
1938 | 1
1983 | 1
Updated question (dupes across multiple rows)
To aggregate values you need a subquery (or CTE).
Simplified test case:
CREATE TEMP TABLE carts(c_id serial, items hstore);
INSERT INTO carts(items) VALUES
('"1614"=>"100", "1938"=>"50", "1983"=>"100", "1322"=>"10", "1691"=>"25", "1734"=>"20"')
,('"1614"=>"50"');
Query:
SELECT item_ids, count(*) AS ct, sum(items) AS sum_items
FROM (
SELECT (each(items)).key AS item_ids
,(each(items)).value::int AS items -- assuming values can be cast to int
FROM carts
) sub
GROUP BY 1 -- positional parameter is just a notational convenience
ORDER BY 2 DESC;
Result:
item_ids | ct | sum_items
----------+----+-----------
1614 | 2 | 150
1734 | 1 | 20
1691 | 1 | 25
1983 | 1 | 100
1938 | 1 | 50
1322 | 1 | 10